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if x+y=a, x2+y2 and x3+y3=c3 then show that a3+2c3=3ab2
L.H.S = a3+2c3 =(x+y)3+2(x3+y3) =x3+3x2y+3xy2+y3+2x3+2y3 =3x3+3x2y+3xy2+3y3 =3(x3+x2y+xy2+y3) =3{x2(x+y)+y2(x+y)} =3(x+y) (x2+y2) =3ab2 =R.H.S ∴L.H.S=R.H.S(Showed)
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